4[x+(2-3x)]=2(4-4x)

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Solution for 4[x+(2-3x)]=2(4-4x) equation: 


Simplifying
4[x + (2 + -3x)] = 2(4 + -4x)

Remove parenthesis around (2 + -3x)
4[x + 2 + -3x] = 2(4 + -4x)

Reorder the terms:
4[2 + x + -3x] = 2(4 + -4x)

Combine like terms: x + -3x = -2x
4[2 + -2x] = 2(4 + -4x)
[2 * 4 + -2x * 4] = 2(4 + -4x)
[8 + -8x] = 2(4 + -4x)
8 + -8x = (4 * 2 + -4x * 2)
8 + -8x = (8 + -8x)

Add '-8' to each side of the equation.
8 + -8 + -8x = 8 + -8 + -8x

Combine like terms: 8 + -8 = 0
0 + -8x = 8 + -8 + -8x
-8x = 8 + -8 + -8x

Combine like terms: 8 + -8 = 0
-8x = 0 + -8x
-8x = -8x

Add '8x' to each side of the equation.
-8x + 8x = -8x + 8x

Combine like terms: -8x + 8x = 0
0 = -8x + 8x

Combine like terms: -8x + 8x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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